Question: Which query bypasses the first 5 customers and returns the next 10?

1. `db.customers.find({}, {skip: 5, limit: 10})`
2. `db.customers.find({}.page(5).take(10))`
3. `db.customers.find({}).skip(5).take(10)`
4. `db.customers.find({}).skip(5).limit(10)`

Answer: The correct answer of the above question is Option D:`db.customers.find({}).skip(5).limit(10)`