Question: What would be the output of this code?

1. There is no output. The code causes a compiler error because `nums` is an array of references, which is illegal.
2. 846
3. The output is the addresses of `i2`, `i0`, and `i1`, in that order, with no spaces.
4. 468

Answer: The correct answer of the above question is Option A:There is no output. The code causes a compiler error because `nums` is an array of references, which is illegal.