Question: The php not operator is !. Given the snippet, is there an out put and what is it?

1. there is an output '2 is an even number
2. output '21 is an odd number'
3. no output. Syntax error do to missing semicolon at the end
4. no output due to % in \$num%2!=0

Answer: The correct answer of the above question is Option B:output '21 is an odd number'