Question: jQuery has a main function for handling AJAX, and several shorthand function including `load()` that make calling that main function easier. Given this HTML snippet, how can you insert only the second snippet from the source.html file (`div#one`) into the `#load-me` div on-demand via AJAX?

1. `$('#load-me').get('source.html#one');`
2. `$('#load-me').get('source.html #one');`
3. `$('#load-me').load('source.html #one');`
4. `$('#load-me').load('source.html', '#one');`

Answer: The correct answer of the above question is Option C:`$('#load-me').load('source.html #one');`